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Trigonometry Basics – Understanding Triangles

Learn how to use sine, cosine, and tangent to find unknown sides and angles in right triangles.

Last updated: 26 January 2026

★★☆☆☆ Level 2TrigonometryLessonSineCosineTangentRight Triangle3 min read

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Why Trigonometry?

Trigonometry lets us find unknown sides or angles in right triangles without measuring directly.

The Three Ratios

In a right triangle with angle θ\theta:

sin⁡θ=oppositehypotenuse,cos⁡θ=adjacenthypotenuse,tan⁡θ=oppositeadjacent\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}, \quad \cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}, \quad \tan\theta = \frac{\text{opposite}}{\text{adjacent}}

Tip

Memory: SOH-CAH-TOA

Finding a Missing Side

If you know one angle (other than the right angle) and one side, you can find the others.

  1. 1

    Label the sides

    Identify opposite, adjacent, and hypotenuse relative to your angle.

  2. 2

    Choose the correct ratio

    Which two sides are involved? Pick sin, cos, or tan accordingly.

  3. 3

    Set up the equation and solve

    Rearrange to find the unknown side.

Right triangle: angle 40°, hypotenuse 10 cm. Find the opposite side.

sin⁡40°=opp/10\sin 40° = \text{opp}/10

opp=10sin⁡40°≈10×0.643=6.43 cm\text{opp} = 10 \sin 40° \approx 10 \times 0.643 = 6.43 \text{ cm}

Finding a Missing Angle

Use inverse trig functions: θ=arcsin⁡(x)\theta = \arcsin(x), arccos⁡(x)\arccos(x), or arctan⁡(x)\arctan(x).

Opposite = 5, adjacent = 12. Find the angle.

tan⁡θ=5/12\tan\theta = 5/12

θ=arctan⁡(5/12)≈22.6°\theta = \arctan(5/12) \approx 22.6°

Real world: measuring a building's height

A surveyor stands 40 m from the base of a tower. The angle of elevation to the top is 28°. Using tangent: height=40×tan⁡28°≈40×0.532=21.3 m\text{height} = 40 \times \tan 28° \approx 40 \times 0.532 = 21.3\text{ m}. Trigonometry lets engineers measure heights that are impractical to climb.

Real world: wheelchair ramp design

A ramp must rise 0.75 m over a horizontal distance of 6 m. The angle of incline: θ=arctan⁡ ⁣(0.756)≈7.1°\theta = \arctan\!\left(\frac{0.75}{6}\right) \approx 7.1°. Building regulations specify a maximum angle (typically ≤ 5°), so trigonometry ensures accessible design.

Real world: navigation and GPS

A ship travels 50 km on a bearing of N 30° E. The northward component =50cos⁡30°≈43.3 km= 50 \cos 30° \approx 43.3\text{ km} and the eastward component =50sin⁡30°=25 km= 50 \sin 30° = 25\text{ km}. GPS systems use these trigonometric decompositions to compute exact position changes.

Tip Remember SOH-CAH-TOA. Label opposite, adjacent, and hypotenuse relative to the angle you are working with before choosing a ratio.

Practice Problems

Triangle: hypotenuse = 15, angle = 30°. Find adjacent side.

Show answer
adj = 15 cos(30°) = 15 × (√3/2) ≈ 13.0

Opposite = 3, hypotenuse = 5. Find the angle.

Show answer
θ = arcsin(3/5) = arcsin(0.6) ≈ 36.9°

Find tan(60°)

Show answer
tan(60°) = √3 ≈ 1.732