Volume and Surface Area of a Sphere

Volume: $V = \dfrac{4}{3} \times \pi \times 216 = 288\pi \approx 904.8 \text{ cm}^3$

Surface area: $SA = 4 \times \pi \times 36 = 144\pi \approx 452.4 \text{ cm}^2$

A standard football has a circumference of about 69 cm, so its radius is $r = 69 / (2\pi) \approx 11.0$ cm.

Volume: $V = \dfrac{4}{3} \times \pi \times 11^3 = \dfrac{4}{3} \times \pi \times 1{,}331 \approx 5{,}575 \text{ cm}^3$

Manufacturers use this to check that the correct amount of air is inside and to calculate rubber and leather usage.

A spherical LPG storage tank has radius 4 m. Its storage volume:

$V = \dfrac{4}{3} \times \pi \times 64 \approx 268 \text{ m}^3$

That is equivalent to 268,000 litres — engineers use this figure for refill scheduling and safety calculations.

A garden sprinkler sprays water in a hemisphere (half-sphere) with radius 3 m. The volume of the spray zone:

$V_{\text{hemisphere}} = \dfrac{1}{2} \times \dfrac{4}{3}\pi \times 27 = 18\pi \approx 56.5 \text{ m}^3$

Irrigation designers calculate this to ensure complete lawn coverage without gaps or overlap.