Area and Perimeter of a Rectangle

$A = 6 \times 4 = 24 \text{ cm}^2$

$P = 2(6 + 4) = 2 \times 10 = 20 \text{ cm}$

A gardener wants to lay turf in a rectangular garden bed that is 5 m long and 3 m wide.

Area of turf needed: $A = 5 \times 3 = 15 \text{ m}^2$

Fencing needed around the edge: $P = 2(5 + 3) = 16 \text{ m}$

Knowing the area tells you how much turf to order; the perimeter tells you how much edging strip to buy.

A standard football pitch is 105 m long and 68 m wide.

$A = 105 \times 68 = 7140 \text{ m}^2$

$P = 2(105 + 68) = 346 \text{ m}$

Groundstaff use the area to calculate how much grass seed or fertiliser the pitch needs each season. The perimeter determines how much boundary rope or advertising hoarding is required around the edge.

A glazier needs to cut a rectangular pane 1.2 m wide and 0.9 m tall.

$A = 1.2 \times 0.9 = 1.08 \text{ m}^2$

Glass is sold by the square metre. Knowing the exact area lets the glazier quote the correct price and ensures they order just enough material without waste.