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Writing Equations from Word Problems

How to translate word problems into algebraic equations and solve them step by step.

Last updated: 30 December 2025

β˜…β˜…β˜†β˜†β˜† Level 2AlgebraEquationsWord ProblemsVariables4 min read

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The Strategy

  1. 1

    Read and identify the unknown

    Decide what you are looking for. Assign it a letter, e.g. xx.

  2. 2

    Translate words into maths

    Look for keywords: more than (+), less than (βˆ’), times (Γ—), divided by (Γ·), is / equals (=).

  3. 3

    Write the equation

    Build the equation from the translated parts.

  4. 4

    Solve and check

    Solve algebraically, then substitute back to verify.

Keyword Guide

Word/phraseOperation
sum, more than, increased by, added to++
difference, less than, decreased byβˆ’-
product, times, ofΓ—\times
quotient, divided by, perΓ·\div
is, equals, gives, results in==
twice, doubleΓ—2\times 2
half ofΓ·2\div 2

A number increased by 7 equals 15. Find the number.

Let xx = the number.

x+7=15x + 7 = 15

x=15βˆ’7=8x = 15 - 7 = 8

Three times a number minus 4 is 11. Find the number.

3xβˆ’4=113x - 4 = 11

3x=153x = 15

x=5x = 5

Ana is 6 years older than her brother. Their ages add up to 28. How old are they?

Let brother's age =x= x. Ana's age =x+6= x + 6.

x+(x+6)=28x + (x + 6) = 28

2x+6=282x + 6 = 28

2x=22β‡’x=112x = 22 \Rightarrow x = 11

Brother is 11, Ana is 17.

Real-World Applications

Real world: Train tickets

An adult train ticket costs €3 more than a child ticket. Two adults and one child pay €19 total. Let the child ticket cost xx: 2(x+3)+x=19β€…β€ŠβŸΉβ€…β€Š3x+6=19β€…β€ŠβŸΉβ€…β€Š3x=13β€…β€ŠβŸΉβ€…β€Šxβ‰ˆ4.33Β EUR2(x + 3) + x = 19 \implies 3x + 6 = 19 \implies 3x = 13 \implies x \approx 4.33\text{ EUR}.

Real world: Mobile data add-ons

A plan includes 2 GB for €10, with extra data at €4 per GB. A customer's bill is €26. How much extra data did they use? 4g+10=26β€…β€ŠβŸΉβ€…β€Š4g=16β€…β€ŠβŸΉβ€…β€Šg=44g + 10 = 26 \implies 4g = 16 \implies g = 4 extra GB.

Real world: Sports match scoring

A basketball team scored twice as many points in the second half as in the first. The full-game total was 72 points. Let pp = first-half points: p+2p=72β€…β€ŠβŸΉβ€…β€Š3p=72β€…β€ŠβŸΉβ€…β€Šp=24p + 2p = 72 \implies 3p = 72 \implies p = 24 in the first half and 48 in the second.

Tip

Where do you see this? Comparing phone or internet tariffs, splitting costs between friends, calculating distances from speed and time, quantities in recipes or shopping.

Practice Problems

A number divided by 4 is 9. What is the number?

Show answer
x / 4 = 9 β†’ x = 36.

Two numbers differ by 5 and their sum is 23. Find both numbers.

Show answer
Let the numbers be x and x + 5. x + x + 5 = 23 β†’ 2x = 18 β†’ x = 9. Numbers are 9 and 14.

A cinema ticket costs €3 more than a bus ticket. Together they cost €11. Find both prices.

Show answer
Bus = x, Cinema = x + 3. x + x + 3 = 11 β†’ 2x = 8 β†’ x = 4. Bus €4, Cinema €7.